@clcoding Answer:B. Explanation:
TLDR:
s.replace('e', 'r', 1) returns a copy of s in which only the first 'e' is replaced by 'r'.
Hence the output is 'awrsome', Option B.
Detailed answer, read on:
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TLDR:
s.replace('e', 'r', 1) returns a copy of s in which only the first 'e' is replaced by 'r'.
Hence the output is 'awrsome', Option B.
Detailed answer, read on:
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@clcoding The str.replace method returns a copy of the string, with certain occurrences of a specified substring replaced by another specified substring.
Here the replace method is called on s, the string "awesome".
So we understand that we will get a copy with certain replacements.
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Here the replace method is called on s, the string "awesome".
So we understand that we will get a copy with certain replacements.
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@clcoding str.replace takes 2 required arguments.
The two required arguments are strings
1⃣ `old`: the substring to be replaced in the string
2⃣ `new`: the substring that will replace `old`
By default, all occurrences of `old` are replaced by `new`
For more control, str.replace takes
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The two required arguments are strings
1⃣ `old`: the substring to be replaced in the string
2⃣ `new`: the substring that will replace `old`
By default, all occurrences of `old` are replaced by `new`
For more control, str.replace takes
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@clcoding For more control, str.replace takes an optional argument, called `count`.
This is an integer that specifies at most how many occurrences of `old` are to be replaced by `new`.
Only the first `count` instances of `old` in s will be replaced by `new`.
The occurrences beyond
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This is an integer that specifies at most how many occurrences of `old` are to be replaced by `new`.
Only the first `count` instances of `old` in s will be replaced by `new`.
The occurrences beyond
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@clcoding The occurrences beyond the first `count` are left un-replaced.
In the question, s.replace('e','r',1) will:
Return a modified copy of s where
'e' will be replaced by
'r'
1 number of times (at most)
Performing this operation, we get the output
'awrsome', Option B
More points
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In the question, s.replace('e','r',1) will:
Return a modified copy of s where
'e' will be replaced by
'r'
1 number of times (at most)
Performing this operation, we get the output
'awrsome', Option B
More points
+
@clcoding More points about s.replace
✔️s itself is not modified at all (strings are immutable)
✔️a modified copy is returned
✔️There is no error if `old` is not in s
✔️There is no error if there are less than `count` occurrences of `old` in s
✔️If you set `count` to a negative integer
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✔️s itself is not modified at all (strings are immutable)
✔️a modified copy is returned
✔️There is no error if `old` is not in s
✔️There is no error if there are less than `count` occurrences of `old` in s
✔️If you set `count` to a negative integer
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@clcoding ✔️If you set `count` to a negative integer, all occurrences of `old` in s are replaced by `new`.
✔️The default value of `count` is -1, which thus replaces all occurrences.
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✔️The default value of `count` is -1, which thus replaces all occurrences.
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@clcoding I hope you found this answer useful.
Another thread on str.replace is linked here, you may want to check that out. These same things are explained a bit differently there.
Follow me for more on Python!
Another thread on str.replace is linked here, you may want to check that out. These same things are explained a bit differently there.
Follow me for more on Python!
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